117笔记1，斐波那契数列把一个88的方格切成四块拼成一个513的长方形
10个
2，99x8 8用乘法分配律怎么做
99*8+8=8*（99+1）=8*100=800
99*99+99=99*99+99*1=99(99+1)=99*100=9900
3，括号1008括号陈125用简便方法计算
（-1/2）+49*（1/2）=24；
括号100-8括号陈125用简便方法计算括号100-8括号陈125=125*100-125*8=12500-1000=11500
4，183888188
(1/8*3√-8*√8-8√1/8)/√8=(1/8*-2*√8-8√1/8)/√8=(-1/4*√8-8√1/8)*1/√8=-1/4*√8*1/√8-8√1/8*1/√8=-1/4-8*1/8=-1/4-1=-5/4
你好！解：原式=[1/8*(-2)*2√2-2√2]/2√2 =（-√2/2-2√2）/2√2 =-5/4希望对你有所帮助，望采纳。
5，8x2等于多少要详细的计算方法
(8-x)2=64-16x+X2
(8-x)2=(8-x)(8-x)=8*8-8x-8x+x^2=64-16x+x^2
x2＋42=﹙8-x﹚2x2+42=64-16x+x2x2-x2+16x=64-1616x=48x=3
式子不完整，还差点东西，只能打开括号 x2-16x+64
(8-x)2=x2-16x+64
6，361118888的简便方法
36?111+888?8=36?111+111×8?8=36?111+111×64=111×(36+64)=111×100=11100
把111提出来，变成36*111+111*8*8 得，36*111+111*64得 111*（36+64）得111*100得 11100
根据题意36*111+888*8=36*111+8*111*8=111*（36+8*8）=111*100=11100
7，51单片机Led点阵88显示一个字的程序是什么 请讲讲程序内容里的
#include<reg52.h>char code yd[]=0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x03,0x00,0x01,0x00,0x00,0x00,//生[16*16]上下列排0x00,0x82,0x03,0x02,0x0c,0x42,0x78,0x42,0x08,0x42,0x08,0x42,0x08,0x42,0xff,0xfe,0x08,0x42,0x08,0x42,0x08,0x42,0x08,0xc2,0x18,0x42,0x08,0x06,0x00,0x02,0x00,0x00,//一[16*16]上下列排0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x01,0x00,0x03,0x00,0x01,0x00,0x00,0x00,//世[16*16]上下列排0x04,0x00,0x04,0x00,0x04,0x00,0x7f,0xfe,0x04,0x02,0x04,0x02,0x04,0x02,0xff,0xf2,0x04,0x22,0x04,0x22,0x04,0x22,0xff,0xf2,0x04,0x06,0x0c,0x02,0x04,0x00,0x00,0x00,//我[16*16]上下列排0x04,0x00,0x24,0x10,0x24,0x12,0x24,0x21,0x7f,0xfe,0xc4,0x40,0x44,0x84,0x04,0x08,0xff,0x90,0x04,0x60,0x44,0x58,0x35,0x86,0x04,0x01,0x0c,0x07,0x04,0x00,0x00,0x00,//爱[16*16]上下列排0x02,0x00,0x0d,0x00,0x49,0x02,0x69,0x0c,0x59,0x31,0x49,0xc1,0x4f,0x62,0x79,0x54,0x49,0x48,0x89,0x54,0x99,0x64,0xa9,0x42,0x89,0x03,0x0a,0x02,0x0c,0x00,0x00,0x00,//你[16*16]上下列排0x02,0x00,0x04,0x00,0x1f,0xff,0xe0,0x00,0x02,0x00,0x04,0x10,0x18,0x20,0xf0,0xc2,0x10,0x01,0x13,0xfe,0x10,0x00,0x10,0x80,0x14,0x60,0x18,0x30,0x00,0x00,0x00,0x00};//延时x msvoid delay(int x) int i,j; for(i=0;i<x;i++) for(j=0;j<120;j++);}main() int i,t,k; while(1) for(i=0;i<16;i++) p1=i; p0=~yd[2*i+2*k]; p2=~yd[2*i+1+2*k]; delay(2); } p2=0xff; p0=0xff; } k=k+1; if(k>96) k=0;} }这个是仿真仿出来的，如果用74hc595的话，程序就不同了~！
在8X8点阵LED上显示柱形，让其先从左到右平滑移动三次，其次从右到左平滑移动三次，再次从上到下平滑移动三次，最后从下到上平滑移动三次，如此循环下去。1． 程序设计内容8X8点阵LED工作原理说明 :8X8点阵共需要64个发光二极管组成，且每个发光二极管是放置在行线和列线的交叉点上，当对应的某一列置1电平，某一行置0电平，则相应的二极管就亮；因此要实现一根柱形的亮法，如图49所示，对应的一列为一根竖柱，或者对应的一行为一根横柱，因此实现柱的亮的方法如下所述：一根竖柱：对应的列置1，而行则采用扫描的方法来实现。一根横柱：对应的行置0，而列则采用扫描的方法来实现。